Find the distance of a point P(x,y) from the origin.
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the distance between point P(x,y)and origin O(0,0)
PO=√(0–x) ²+(0–y) ²
PO=√(–x)²+(–y) ²
PO=√x²+y²
hope this helps you.....
PO=√(0–x) ²+(0–y) ²
PO=√(–x)²+(–y) ²
PO=√x²+y²
hope this helps you.....
Answered by
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hey dear
here is your answer
distance of point P ( x, y)
points of origin Q (0,0)
we use distance formula
√(x2 -x1) square + √( y2 -y1)square
√( 0 -x1)square + √ (0-y1) square
so it comes
√x^2 +y^2
it is the answer
hope it helps
thank you
here is your answer
distance of point P ( x, y)
points of origin Q (0,0)
we use distance formula
√(x2 -x1) square + √( y2 -y1)square
√( 0 -x1)square + √ (0-y1) square
so it comes
√x^2 +y^2
it is the answer
hope it helps
thank you
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