find the distance of a point p (x,y) from the origin.
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Answered by
12
Hey friend!
Here's your answer
===================>
Given P ( x,y ) be the x1 , y1
and let the origin be the (0,0) say x2 , y2
Now , by using distance formula
√ (x2-x1)²+ ( y2-y1 ) ²
after simplifying we get the answer
√x²+y²
# Hope it helps #
Here's your answer
===================>
Given P ( x,y ) be the x1 , y1
and let the origin be the (0,0) say x2 , y2
Now , by using distance formula
√ (x2-x1)²+ ( y2-y1 ) ²
after simplifying we get the answer
√x²+y²
# Hope it helps #
Answered by
10
Hey there!
We know that, Distance between P(a,b) and Q(c,d) = √ ( c - a)² + ( d - b) ²
Origin = ( 0 , 0 )
Point P = ( x, y)
Now, Distance = √ ( x - 0)² + (y-0)²
= √ x² + y²
Therefore ,The required distance = √ x²+y²
We know that, Distance between P(a,b) and Q(c,d) = √ ( c - a)² + ( d - b) ²
Origin = ( 0 , 0 )
Point P = ( x, y)
Now, Distance = √ ( x - 0)² + (y-0)²
= √ x² + y²
Therefore ,The required distance = √ x²+y²
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