Question

Find the distance of a point P(x,y) from the origin O(0,0)

 ​

Answer 1

Answer:

Thus the distance of the point P(x,y) from the origin O(0,0) is x2+y2.

Answer 2

Answer:

$\sqrt{x^{2} +y^{2} }$

Step-by-step explanation:

Let O be the origin and Q be the foot of the perpendicular dropped from P onto the x axis.  

So ΔOPQ is right-angled at Q.

By definition of coordinates:

OQ=x coordinate of P= distance of P from y axis =∣x∣

Similarly, QP=∣y∣.

Thus, by using Pythagoras theorem on ΔOPQ, we get OP= $\sqrt{x^{2} +y^{2} }$