Question

find the distance of aP(x,y)fromthe origin

Answer 1

Hey mate !!

Here's your answer !!

Distance formula = √ ( X - x )² + ( Y - y ) ²

= √( X - 0 )² + ( Y - 0 )²

= √ ( X )² + ( Y )²

= √ X² + Y²

Hope this helps !!

Cheers !!

Answer 2

Given:

Point ( x, y )

Origin ( 0, 0 )

To find:

The distance.

Solution:

By formula

Distance between two points = √(( y2 - y1 )^2 + ( x2 - x1 )^2)

Origin ( 0, 0 ) ( x1, y1 )

Point ( x, y ) ( x2, y2 )

Distance = √(( y - 0 )^2 + ( x - 0 )^2

√(x)^2 + (y)^2  

Hence, the distance of a point P(x,y) from the origin is √(x)^2 + (y)^2.

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