find the distance of each point origin A(-5,5)
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Answered by
9
Heya !!
Let A( -5 , 5 ) be the given point and O(0,0) be the origin.
Therefore,
OA = ✓(-5 - 0)² + (5 - 0)²
OA = ✓(-5)² + (5)²
OA = ✓25+25
OA = ✓50 = ✓2 × 5 × 5
OA = 5✓2 unit's.
Hence,
Distance between point A(-5,5) from the origin is 5✓2 unit's.
Let A( -5 , 5 ) be the given point and O(0,0) be the origin.
Therefore,
OA = ✓(-5 - 0)² + (5 - 0)²
OA = ✓(-5)² + (5)²
OA = ✓25+25
OA = ✓50 = ✓2 × 5 × 5
OA = 5✓2 unit's.
Hence,
Distance between point A(-5,5) from the origin is 5✓2 unit's.
Answered by
5
Hi dear
★ Here is your answer ★
Suppose A( -5 , 5 ) be the given point and O(0,0) be the origin.
OA = ✓(-5 - 0)² + (5 - 0)²
OA = ✓(-5)² + (5)²
OA = ✓50 = ✓2 × 5 × 5
OA = 5✓2 units.
Distance between point A(-5,5) from the origin is 5✓2 units.
Hope it helps you ^_^
★ Here is your answer ★
Suppose A( -5 , 5 ) be the given point and O(0,0) be the origin.
OA = ✓(-5 - 0)² + (5 - 0)²
OA = ✓(-5)² + (5)²
OA = ✓50 = ✓2 × 5 × 5
OA = 5✓2 units.
Distance between point A(-5,5) from the origin is 5✓2 units.
Hope it helps you ^_^
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