Math, asked by shahanfauzia, 6 months ago

find the distance of man from the foot of tower 100m high if the angle of elevation of its top as observed by the man is 52°32'?

Answers

Answered by akshitatewari24

0

Answer:

Step-by-step explanation: of tower = BC = 100m in right

ABC.

Tan 52o

32‟ =

BC

AB

1.3032 =

100

AB

 AB =

100

1.3032

= 78.73m

AB = distance of man from the

foot of tower = 76.73m

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