Question

find the distance of p(3,-2,4) from the origin

Answer 1

root({ 3-0  }^2+ (-2-0)^2+ (4-0)^2)=root(29)

Answer 2

$The\ distance\ formula:A(x_A;\ y_A;\ z_A);\ B(x_B;\ y_B;\ z_B)\\\\|AB|=\sqrt{(x_B-x_A)^2+(y_B-y_A)^2+(z_B-z_A)^2}\\------------------------------\\\\A(0;\ 0;\ 0);\ B(3;-2;\ 4)\\\\|AB|=\sqrt{(3-0)^2+(-2-0)^2+(4-0)^2}\\\\=\sqrt{3^2+(-2)^2+4^2}=\sqrt{9+4+16}=\sqrt{29}$