Question

Find the distance of point (3,-5) from the line 3x-4y-26=0

Answer 1

Answer:

Required Distance =

$\frac{ |3 \times 3 + 4 \times 5 - 26| }{ \sqrt{ {3}^{2} + {4}^{2} } } = \frac{29 - 26}{5} = \frac{3}{5} \: \: ans.$