find the distance of point (6,8)and the origin
Answers
Answered by
9
it is √{(x2-x1)²+(y2-y1)²}
so √(36+64)
√100
=10 units
therefore distance between origin and (6,8)
is 10 units
hope it helps
plz mark it as brainliest
so √(36+64)
√100
=10 units
therefore distance between origin and (6,8)
is 10 units
hope it helps
plz mark it as brainliest
Answered by
2
Using pythagoras theorem,
8²+6² =hypotenuse²
⇒64+36 = 100
√100 =10
10 units
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