Question

find the distance of point A(3,-5) from x axis.

Please write the steps!​

Answer 1

Answer:

here is the answer to your question.

Hope it helps.

P.S. sorry for the bad handwriting, but I hope you will understand what I wrote.

Answer 2

Distance of the point is:

$\sqrt{ \left ( a-3 \right )^2+ 25}$ where $a$ is constant.

Step-by-step explanation:

Let us assume the coordinate on $x -\text{axis}$ be $(a,0)$ where $a$ is constant.

The distance between two points $\left ( x_1,y_1 \right ) \text{and} \left ( x_2,y_2 \right )$ is $\sqrt{ \left ( x_2-x_1 \right )^2+ \left ( y_2-y_1 \right )^2}$

Here, $\left ( x_1,y_1 \right )=\left ( 3,-5 \right )$ and $\left ( x_2,y_2 \right )=\left ( a,0 \right )$

The distance between given points is $\sqrt{ \left ( a-3 \right )^2+ \left ( 0+5 \right )^2}$

$\Rightarrow \sqrt{ \left ( a-3 \right )^2+ \left ( 0+5 \right )^2}=\sqrt{ \left ( a-3 \right )^2+ 25}$

For example - Let us take $a=10$,

The distance between points is $\sqrt{ \left ( 10-3 \right )^2+ 25}=\sqrt{ 49+ 25}$

                                                                               $=\sqrt{ 74}$

For example - Let us take $a=-5$,

The distance between points is $\sqrt{ \left ( -5-3 \right )^2+ 25}=\sqrt{ 64+ 25}$

                                                                                 $=\sqrt{ 89}$

Learn more:

Coordinates: https://brainly.in/question/15894866