Question

find the distance of point p(-1,5) from x axis

Answer 1

Answer:

distance=√(X-x)²+(Y-y)²

     =√0+25

⇒distance=5 units

Answer 2

The distance of point p(-1,5) from the x-axis is 5 unit.

Step-by-step explanation:

To find : The distance of point p(-1,5) from x axis ​?

Solution :

The distance of a point P(a,b) from x-axis is given by the y-coordinate of the point.

i.e. d=|b|

Here, the point is P(a,b)=(-1,5)

The y-coordinate is 5.

The distance of point p(-1,5) from x axis is d=|5|= 5 unit.

Therefore, the distance of point p(-1,5) from the x-axis is 5 unit.

#Learn more

Find the point on the x axis which is equal distance from ( 2,-5) (-2,9)

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