Math, asked by harshittripathi8067, 1 year ago

Find the distance of point p (6, - 6) form the origin

Answers

Answered by Anonymous
100

 \sqrt{ {x}^{2} +  {y}^{2}  }  \\  =  \sqrt{ {6}^{2} +  { (- 6)}^{2}  }  \\  =  \sqrt{72}   \\  = 6 \sqrt{2}
Answered by Amandeepkumar6200112
30

Answer:if a point p(x, y) is equidistant from the points A(6,-1) and B(2,3) find the relation between X and Y.



Step-by-step explanation:


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