Question

find the distance of point P (-6,8) from the origin ?​

Answer 1

The distance of the point P(−6,8) from the origin is

$\sqrt{6 {}^{2} } + 8 ^{2}$

=√36+64=√100= 100units...

Answer 2

Answer:

The distance of the point P(−6,8) from the origin is 62+82 =36+64 =100 =10

Step-by-step explanation:

The distance of the point P(−6,8) from the origin is

√-6^2+8^2=√36+64

=√100

= 10