Question

find the distance of point p (x, y)from the origin

Answer 1

we have point P(x,y) and O(0,0) 

PO = root (x-0)^2 + (y-0)^2
PO = root x^2 + y^2

hope it helps!!
please mark as brainliest ...

Answer 2

The distance of point p(x, y) from the origin is $\sqrt{x^2+y^2}$

Step-by-step explanation:

To find : The distance of point p (x, y) from the origin ?

Solution :

The distance formula between two points $A(x_1,y_1)$ and $B(x_2,y_2)$ is given by,

$d(A,B)=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Here, the points are $p(x_1,y_1)=(x,y)$ and $o(x_2,y_2)=(0,0)$

Substitute the values,

$d(p,0)=\sqrt{(0-x)^2+(0-y)^2}$

$d(p,0)=\sqrt{x^2+y^2}$

Therefore, the distance of point p(x, y) from the origin is $\sqrt{x^2+y^2}$

#Learn more

Find the relation between x and y such that the distance of point p(x,y) and (3,6)is twice the distance between the points p(x,y) and (-3,4)

https://brainly.in/question/5382381