Question

Find the distance of (sec60°,sin30°) from the origin​

Answer 1

Step-by-step explanation:

Distance from P (x, y) to origin

Points of origin Q (0,0)

By applying distance formula

$= \sqrt{ {x}^{2} + {y}^{2} }$

$= \sqrt{ { \sec(60) }^{2} + { \sin(30) }^{2} }$

$= \sqrt{ { {2} }^{2} + { \frac{1}{ {2} } }^{2} }$

$= \sqrt{} 4 + \frac{1}{4}$

$= \sqrt{ \frac{17}{4} } = \frac{ \sqrt{17} }{2}$