Question

Find the distance of the chord of length 8cm from the centre of the circle of radius 5cm with figure

Answer 1

AO =5 CM
AN =8CM
IN TRIANGLE ABC


(AO)^2=(AP)^2+(OP)^2

5^2=4^2. + OP^2. {AP= 1/2AB =4 CM }

25=16. +OP^2

OP^2 =25-16. =9

OP=3 cm


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Answer 2

Step-by-step explanation:

Refer to attachment

Hope it helps you