Question

Find the distance of the image when an object is placed on the principal axis at a distance of 10 cm infront of a concave mirror whose radius of curvature is 8 cm.​

Answer 1

Here, u=10cm,f=r/2=8/2=4cm
By mirror formula,
$1 \div f = 1 \div v + 1 \div u$
1/4=1/v +1/10
1/4 - 1/10=1/v
(10-4)÷40=1/v. [(10-4)÷40 by cross multiplying]
6÷40=1/v
V=40÷6
V=6.66cm