find the distance of the image when an object is placed on the principle axis at a distance of 10cm infront of a concave mirror whose radius of curvature is 8.? draw a ray diagram also........
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object's distance = u = -10cm
focal length = f = -4cm
image distance=v
now by mirror formula
1/f= 1/v-1/u
1/-4 = 1/v-1/-10
-1/4=1/v+1/10
1/v=-(1/4+1/10)
1/v=-(14/40)
v=-40/14
v=-20/7
hope this help:p
focal length = f = -4cm
image distance=v
now by mirror formula
1/f= 1/v-1/u
1/-4 = 1/v-1/-10
-1/4=1/v+1/10
1/v=-(1/4+1/10)
1/v=-(14/40)
v=-40/14
v=-20/7
hope this help:p
sravan6:
wt is final answer
distance is20/7 cm
of image..
can u draw it un ray diagram
Please
u can made it by urself only man...its simple...take help from the book..
but.i can't.
i did not understanding yarrr.
hey I have done a mistake in my answer....I have used lens formula in place of mirror formula so I m editing it..
sry I m not able to edit it...
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