Question

find the distance of the image when an object is placed on the principal axis at a distance of 10cms in front of concave mirror whose radius of curvature is 8cms​

Answer 1

Answer:

v = 6.67

Explanation:

U = 10cm

R = -8cm

f = r/2

f = -8/2

f = -4

1/f = 1/u + 1/v

1/v = 1/f +-1/u

1/v = 1/-4 + 1/10

1/v = 10-4/-40

1/v = 6/-40

v = -40/6

v = 6=67

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