Question

find the distance of the image whrn an object is placed on tge principle axis at a distance of 10 cm infront of a concave mirror whose radius of curvature is 8 cm.​

Answer 1

Explanation:

u = - 10 cm

r = -8 cm

f = r/2

f = -4 cm

v = ?

according to mirror formula

1/v + 1/u = 1/f

1/v + 1/-10 = 1/-4

1/v - 1/10 = -1/4

1/v = -1/4 + 1/10

1/v = -5 + 2 /20

1/v = -3 / 20

v = -20/3

v = 6.6