Question

find the distance of the line 4x+3y+5=0 from the origin.​

Answer 1

Step-by-step explanation:

The distance d between the line ax+by+c=0 and point (x

1

,y

1

) is given by

d=∣

a

2

+b

2

ax

1

+by

1

+c

∣

Therefore, Required distance=∣

4

2

+(−3)

2

4(2)−3(1)+5

∣=

5

10

=2

Option B is correct.