Question

Find the distance of the line 4x-y=0 from the point p(4 1)

Answer 1

Answer:

15/√17

Step-by-step explanation:

Distance of a point(x1,y1) fron line

ax+by+c=0 is given by

(ax1+by1+c)/√a²+b²

Here the equation can be written as:

4x-y+0=0

a=4,b=-1,c=0

so distance from(4,1) is:

=(4*4-1*1+0/√4²+1²

=16-1/√17

=15/√17