Find the distance of the origin from the line 12x+5y+78=0
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9
Answer:
Given: Coordinate of origin (0,0) and Equation of line
12x + 5y + 78 = 0
We know formula for distance between a point and line is
Distance = |Ax+By+C|/(√(A^2 )+ B^2 )
Distance = |12×0+5×0+78|/(√(〖12〗^2 )+ 5^2 )
Distance = |0+0+78|/√169
Distance = |78|/√(13×13)
Distance = |78|/13
Distance = 6
So the distance between origin and line 12x + 5y + 78 = 0 is 6.
Answered by
0
Answer:
12x +5y+78=0
is correct
answer is 6 units
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