Math, asked by khsuhi26, 1 year ago

Find the distance of the origin from the line 12x+5y+78=0​

Answers

Answered by Dhruv4886
9

Answer:

Given: Coordinate of origin (0,0) and Equation of line

12x + 5y + 78 = 0

We know formula for distance between a point and line is

                           Distance = |Ax+By+C|/(√(A^2 )+ B^2 )

                           Distance = |12×0+5×0+78|/(√(〖12〗^2 )+ 5^2 )

                           Distance = |0+0+78|/√169

                           Distance = |78|/√(13×13)

                           Distance = |78|/13

                           Distance = 6  

So the distance between origin and line 12x + 5y + 78 = 0 is 6.

Answered by mhatreom343
0

Answer:

12x +5y+78=0

is correct

answer is 6 units

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