Question

Find the distance of the origin from the line 3x+4y+15=0

Answer 1

Answer:

good morning dear have a good day

Answer 2

Answer:

3x + 4y + 15 = 03x+4y+15=0

3x + 4y = - 153x+4y=

​

−15

3x

​

+

−15

4y

​

=1

\frac{x}{ \frac{ - 15}{3} } + \frac{y}{ \frac{ - 15}{4} } = 1

3

−15

​

x

​

+

4

−15

​

y

​

=1