Find the distance of the plane 2 x minus 3 y + 4 z - 6 is equal to zero from the origin
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Three Dimensional Geometry Find the distance of the plane 2x – 3 y + 4 z – 6 = 0 from the origin. Direction ratios of the normal to the plane (1) are 2, – 3, 4. This is of the form lx + my + nz = p, where p is the distance of the plane from the origin.
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