find the distance of the point (1,-2) from the line 12x - 5y + 4 = 0
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The distance between a point and a line is the shortest distance between a fixed point and any point on the line.
The formulae is:
d = ( | a(x₁) + b (y₁) +c | ) /√(a² + b²)
Where ax + by +c is the equation of the line and (x₁, y₁) is the point.
Substituting the given values in the formula we have :
12 × 1 - (5×-2) + 4 = 26
12² + (-5)²=169
√169 =13
26/13= 2units
The formulae is:
d = ( | a(x₁) + b (y₁) +c | ) /√(a² + b²)
Where ax + by +c is the equation of the line and (x₁, y₁) is the point.
Substituting the given values in the formula we have :
12 × 1 - (5×-2) + 4 = 26
12² + (-5)²=169
√169 =13
26/13= 2units
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