Find the distance of the point (1,2)from the mid point of the line segment joining the points (6,8) and (2,4)
Answers
hello users ......
we have to find
the distance of the point (1,2)from the mid point of the line segment joining the points (6,8), (2,4).
solution :-
at first
let the mid point of (6,8), (2,4) is (x,y)
here
x =
=
= 8/2 = 4
and y=
= = 12 / 2= 6
the co-ordinates of mid point are (4,6)
now,
using distance formula
distance between (4,6) and (1,2) is
=
= √(3² + 4²) = √(9 + 16) = √ 25 = 5
Answer:
5
Step-by-step explanation:
let point c(1,2) be at a distance q from point p(x,y) which is the midpoint of a line segment s= joining a(6,8) and b(2,4)
using midpoint formula
x1+x2/2=x | y1+y2/2=y
2+4/2=4 | 4+8/2=6
hence x=4 | y=6
now using distance formula for finding distance q
D(CP)=root over <(x2-x1)^2+(y2-y1)^2>
= root over <(4-1)^2+(6-2)^2>
=root over (9+16)
=root over (25)
=5