Question

find the distance of the point (-3,2)
from x axis​

Answer 1

Step-by-step explanation:

(x,y)=(-3,2)

a point on x axis is (x,0)

let A(-3,2). B(x,0)

therefore the distance between AB is √ (x2-x1)2 + (y2-y1)2

=√(x+3)2+ (0-2)2=√x2 +9+6x+4

√x2+6x+13=0

hope this is helpful plzz mark my answers brainliest