Question

find the distance of the point (3 -5) from the line 3x-4y-26=0

Answer 1

Answer:

$the \: distance \: of \: the \: point \: (3 -5) \: from \: the \: line \: 3x-4y-26=0 \: = \\ \frac{3( 3) - 4( - 5) - 26}{ \sqrt{ {(3)}^{2} + {( - 4)}^{2} } } \\ = \frac{9 + 20 - 26}{ \sqrt{9 + 16} } \\ = \frac{3}{5} \: units$