Find the distance of the point (3,-7)form thepoint (5,-5).
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Distance between two points (x₁, y₁) and (x₂, y₂) is
= √[(x₂-x₁)²+(y₂-y₁)²]
Given that two points are (3, -7) and (5, -5), so distance is
= √[(5-3)²+(-5+7)²]
= √(4+4)
= √8
= 2√2
Hence distance of the point (3,-7) form the point (5,-5) is 2√2.
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Using distance formula
(Y-y1)^2 + (x-x1^2) = r^2
r = root (-5+7)^2 + (5-3)^2
r = root 4+4
r = 2 root 2
(Y-y1)^2 + (x-x1^2) = r^2
r = root (-5+7)^2 + (5-3)^2
r = root 4+4
r = 2 root 2
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