find the distance of the point (-4,3) from the line 4(x+5)=3(y-6)
Answers
Answered by
4
★GOOD EVENING★
EQUATION OF LINE IS 4x - 3y + 38 = 0
It's ( -4 , 3 ) distance from above line is given by this formula.
d = ( ax1 + by1 + c )/ { √(a² + b² ) }
Here a = 4 , b = -3 And c = 38
x1 = -4 And y1 = 3
=>
d =
( 4 × -4 ) + ( -3 × 3 ) + 38
__________________
√(16 + 9 )
=>
d = 13/5 units.
EQUATION OF LINE IS 4x - 3y + 38 = 0
It's ( -4 , 3 ) distance from above line is given by this formula.
d = ( ax1 + by1 + c )/ { √(a² + b² ) }
Here a = 4 , b = -3 And c = 38
x1 = -4 And y1 = 3
=>
d =
( 4 × -4 ) + ( -3 × 3 ) + 38
__________________
√(16 + 9 )
=>
d = 13/5 units.
Answered by
0
Answer:
13/5 UNITS
Step-by-step explanation:
EQUATION OF LINE IS 4x - 3y + 38 = 0
It's ( -4 , 3 ) distance from above line is given by this formula.
d = ( ax1 + by1 + c )/ { √(a² + b² ) }
Here a = 4 , b = -3 And c = 38
x1 = -4 And y1 = 3
d = ( 4 × -4 ) + ( -3 × 3 ) + 38
√(16 + 9 )
d = 13/5 units.
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