find the distance of the point( - 4 ,- 7) from the y-axis
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Answered by
65
Answer: 4 units
Step-by-step explanation:
For a point to lie on the y axis its x coordinate has to be 0
therefore, P(0,-7) Q(-4,-7)
By distance formula,
PQ= √(-4-0)²+(-7+7)²
PQ=√(-4)²+(0)²
PQ=√16+0
PQ=√16
PQ=±4
But since distance cannot be -ve, -4 is rejected
∴PQ=4 units
anshikabhanot03:
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13
Answer:
here it is
Step-by-step explanation:
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