CBSE BOARD X, asked by shantanu7352, 7 months ago

Find the distance of the point (5,-6) from the origin​

Answers

Answered by skoduru25gmailcom
0

Answer:

11 eleven

Explanation:

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Answered by Anonymous
12

Answer:

Answer:

\sqrt{61} \: unit

61

unit

Step-by-step explanation:

As we know that distance formula is used to find the distance between two given points

If point A(x1,y1) and B(x2,y2)

\begin{gathered}AB= \sqrt{ {(x_2 - x_1)}^{2} + {(y_2 - y_1)}^{2} } \\ \\\end{gathered}

AB=

(x

2

−x

1

)

2

+(y

2

−y

1

)

2

Here one point is (-5,6) and other is origin i.e.(0,0)

So,distance

\begin{gathered}= \sqrt{( { - 5 - 0)}^{2} + {(6 -0 )}^{2} } \\ \\ = \sqrt{25 + 36} \\ \\ = \sqrt{61} unit \\ \\\end{gathered}

=

(−5−0)

2

+(6−0)

2

=

25+36

=

61

unit

Hope it helps you.

Explanation:

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