Find the distance of the point 5 ,6 from the origin
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THE X COORDINATE = 5 UNITS
THE Y COORDINATE= 6 UNITS
THE DISTANCE WILL BE THE THE STRAIGHT LINE FROM THE ORIGIN TO THE POINT.
SO,,
(AC)² = (AB)² + (BC)²
(AC)²= 5² + 6²
(AC)² = 25 + 36
(AC)² = 61
AC=
AC = 7.81 units
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