Question

Find the distance of the point (-5,7) form the x_axcis

Answer 1

here distance from x axis could be determined by simple method

we know that the y coordinate is 0 always so

the pint on x - axis becomes {-5,0}

so distance is given by = $\sqrt{[x^{2} -X^{2}]-[y^{2}-Y^{2}] }$

SO distance is $\sqrt{49}}$

which is 7 units

Step-by-step explanation:

Answer 2

here distance from x axis could be determined by simple method

we know that the y coordinate is 0 always so

the pint on x - axis becomes {-5,0}

so distance is given by = \sqrt{[x^{2} -X^{2}]-[y^{2}-Y^{2}] }

[x

2

−X

2

]−[y

2

−Y

2

]

SO distance is $$\sqrt{49}}$$

which is 7 units

Step-by-step explanation