Math, asked by S3h, 1 year ago

Find the distance of the point (-6,8) from the origin

Answers

Answered by TPS
648
distance of the point from origin =

 \sqrt{{( - 6 - 0) }^{2} +  {(8 - 0)}^{2}  }  \\  =  \sqrt{ {6}^{2} +  {8}^{2}  }  \\  =  \sqrt{36 + 64}  \\  =  \sqrt{100 }  \\  = 10
Answered by mysticd
157

Answer:

The distance of the point (-6,8) from the origin = 10

Explanation:

________________________

We know that,

Distance of a point (x,y) from the Origin is \sqrt{x^{2}+y^{2}}

________________________

Now ,

here

Distance of the point (x,y)=(-6,8)

from the origin = \sqrt{(-6)^{2}+8^{2}}

= \sqrt{36+64}

= \sqrt{100}

= \sqrt{10^{2}}

= $10$

Therefore,

The distance of the point (-6,8) from the origin = 10

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