Question

find the distance of the point 6,-9) from the origin​

Answer 1

Answer:

3√13 units

Step-by-step explanation:

Distance of the point (6,-9) from the origin is

= √(6-0)²+(-9-0)² units

= √6²+9² units  

= √(36+81) units

= √117 units

= √(9×13) units

= 3√13 units

Answer 2

Solution :

Using Distance formula

$\text{Distance of point (x,y) from origin d} = \sqrt{ {x}^{2} + {y}^{2} }$

Here

• x = 6
• y = - 9

Substituting the value in the formula

$\implies d = \sqrt{ {6}^{2} + {( - 9)}^{2} }$

$\implies d = \sqrt{ 36 + 81}$

$\implies d = \sqrt{117}$

$\implies d = \sqrt{9 \times 13}$

$\implies d = \sqrt{9} \times \sqrt{13}$

$\implies d = 3\times \sqrt{13}$

$\implies \boxed{d = 3 \sqrt{13} }$

Hence, the distance of the point (6,-9) from the origin is 3√13 units.