Question

find the distance of the point (bcos theta ,bsin theta) from the origin

Answer 1

Hope it will help you....

Answer 2

→Question: The distance of the point  (b cos theta,b sin theta)  from origin is:

→Answer: To find distance, we use the distance formula:

⇒Distance formula: √(x2 - x1)² - (y2 - y1)²

⇒Where:

x2 = bcosθ

x1  = 0

y2 = bsinθ

y1  = 0

⇒Now:

√(bcosθ - 0)² + (bsinθ - 0)²

√b²cos²θ + b²sin²θ

√b²(cos²θ + sin²θ)

b√1

b

⇒ x and y coordinates:

⇒        (0,0)   A______________________________B (bcosθ,bsinθ)

∴The distance between the point bcosθ , bsinθ from the origin is b.

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