Question

Find the distance of the point p(-1,5) from the x-axis

Answer 1

$\textbf{Answer :}$

We will solve this problem in a easy way.

The given point is P (- 1, 5)

The ordinate of the point P is 5

Now, we know that the ordinate of any point determines the perpendicular distance of that point from the x-axis.

Hence, the required perpendicular distance be $\textbf{5 units}$

#$\bold{MarkAsBrainliest}$

Answer 2

P(-1,5)  Q(x,0)

Ordinate of the point P is 5

We know that the ordinate of any point determines the perpendicular distance of that point from the x-axis.

Therefore,

x=5

P(-1,5) and Q(5,0)