Question

find the distance of the point p(2,3,1) and q(-1,3,-5)​

Answer 1

Answer:

Jai shree Ram

Step-by-step explanation:

Jai shree ram

Answer 2

Answer:

Step-by-step explanation: 2  

2

​

 

QR makes equal angles with axis ±  

3

​

 

1

​

 

DR of QR are (±  

3

​

 

1

​

,±  

3

​

 

1

​

,±  

3

​

 

1

​

)

DR of QR are (±1,±1,±1)

⇒QR:  

1

x+3

​

=  

1

y−6

​

=  

1

z−2

​

=t

Foot of perpendicular from P be P  

′

 (t−3,t+6,t+2)

DR's of PP  

′

 are perpendicular to QR

DR's of PP  

′

(t−3−1−2,t+6−3,t+2−1)

=(t−1,t+3,t+1)

PP  

′

 

.  

QR

​

=0

⇒(t−1)+t+3+t+1=0

3t+3=0

t=−1

⇒P  

′

(−4,5,1)

∣PP  

′

∣=  

(−2+4)  

2

+(3−5)  

2

+(1−1)  

2

 

​

=2  

2

​

 

solution