Find the distance of the point p (3,4) and the origin
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√3^2+√4^2=√25=5 unit
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p (3,4) let it be ( X2,Y2)
let origin be O
O (0,0). let it be (X1,Y1)
by distance formula
distance = √(X2. - X1)² + (Y2. -Y1)²
=√(3-0)² + (4-0)²
=√ 3² + 4²
=√ 9 +16
=√25
= 5
let origin be O
O (0,0). let it be (X1,Y1)
by distance formula
distance = √(X2. - X1)² + (Y2. -Y1)²
=√(3-0)² + (4-0)²
=√ 3² + 4²
=√ 9 +16
=√25
= 5
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