Question

find the distance of the point P 34 and the origin

Answer 1

think this can be ur answer!!P(x, y)O (0,0)Now distance of P from O,OP2 =(x-0)2 + (y-0)2= x2 +y2OP =root (x2 ..

Answer 2

Answer: The distance between P(3,4) and origin O(0,0) is  5 units

Step-by-step explanation:

To find: The distance between point P(3,4) and origin O(0,0)

As we know the distance formula between two points is given by

$AB= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Now the distance between P(3,4) and origin O(0,0) is

$PO= \sqrt{(0-3)^2+(0-4)^2} \\\\\Rightarrow PO= \sqrt{(-3)^2+(-4)^2} = \sqrt{3^2+4^2}= \sqrt{9+16} = \sqrt{25} =5$

Therefore PO = 5 units

Hence ,the distance between P(3,4) and origin O(0,0) is  5 units