Question

Find the distance of the point P (4, 2) from origin.​

Answer 1

Answer:   $\sqrt{20}$

Explanation:

x^2=4^2+2^2

x^2=16+4

x^2=20

x= $\sqrt{20}$

Answer 2

Answer:

The distance of the point P (4, 2) from origin (0,0) is 2√5 units.

Explanation:

• We know that the formula to find the distance between two points P(x₁, y₁) and Q(x₂, y₂) is

        Distance = √$(x2-x1)^{2}$+$(y2 - y1)^{2}$........................................(i)

• We have to find the distance of the point P (4, 2) from origin i.e. (0, 0)

• Substituting these values in the equation (i) we get

• Distance=√$(0-(4))^{2}$+$(0-2)^{2}$

So we get,

Distance of point P = √(16 + 4) = √20 = 2√5

Distance of point P from the origin is 2√5 units.