Question

find the distance of the point P(4.3) for y axis.​

Answer 1

Answer:

Given point is P(4,3)

Lets suppose (x1,y1) = (4,3)

&

Required point is Q(x2,y2)

We know that

Since the given point P(4,3) is perpendicular to the point Q(x2,y2)

=> Q(x2,y2) = (4,0)

Distance between points P(x1,y1) and Q(x2,y2) is calculated as,

PQ = √{(x2 - x1)^2 + (y2 - y1)^2}

=> PQ = √{(4 - 4)^2 + (0 - 3)^2}

=> PQ = √(0 + 9)

PQ = 3 that satisfies the conditions.

So the perpendicular distance of point P(4,3) from the x-axis is 3 Unit.

Step-by-step explanation:

Answer 2

Step-by-step explanation:

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