Question

find the distance of the point p(x,y) from the origin​

Answer 1

Answer:

Hence the distance between the origin and the point P is √x2+y2.

Step-by-step explanation:

Let O be the origin and Q be the foot of the perpendicular dropped from P onto the x axis.

So ΔOPQ is right-angled at Q.

By definition of coordinates:

OQ=x coordinate of P= distance of P from y axis =∣x∣

Similarly, QP=∣y∣.

Thus, by using Pythagoras theorem on ΔOPQ, we get OP= OQ^2+QP^2= x^2+y^2

Thus the distance of the point P(x,y) from the origin O(0,0) is √x^2+y^2.