Question

find the distance of the points from origin (-2/5,-1/5)​

Answer 1

Answer:

The distance between the points (−1,5,−5) and (0,0,0) is (−1)2+52+(−5)2=1+25+25=51 units.

Step-by-step explanation:

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Answer 2

Answer:

The required answer is 1

Step-by-step explanation:

ATQ,

Distance formula for finding distance between two points is :

$\sqrt{ { (x_{2} - x_{1}) }^{2} + { (y_{2} - y_{1}) }^{2} }$

Now values given are :

$x_{1} = - 2 \\ y_{1} = 5 \\ x_{2} = - 1 \\ y_{2} = 5$

So , the distance between these two points will be

$= \sqrt{ {( ( - 1) - ( - 2))}^{2} + {(5 - (5))}^{2} }$

$= \sqrt{ {( - 1 + 2) }^{2} + 0}$

$= \sqrt{ { - 1}^{2} }$

$\sqrt{1} = > 1$

Hence the distance between these two points is 1

Hope it helped