CBSE BOARD X, asked by vinukesarkar653, 11 months ago

Find the distance on the x axis which is equidistant from (2,-5) and (-2,9)

Answers

Answered by m003
2

Explanation:

 \sqrt{(x2  -  x1) ^2  +  (y2  -  y1)^2}

 \sqrt{( - 2 - 2)^2 + (9 + 5)^2 }

 \sqrt{( - 4)^2 + (14)^2}

 \sqrt{16 + 196}

 \sqrt{212}

=14.56 cm

Therefore, the distance between two points is 14.56 cm.

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