Question

Find the distance on the X-axis which is equidistant from (2,-5) and (-2,9)

Answer 1

The point on x-axis is (-7,0)

Step-by-step explanation:

Let the point on x-axis be P(a,0)

P is equidistant from A(2,-5) and B(-2,9)

So, PA = PB

$\sqrt{(a-2)^2+(0+5)^2}=\sqrt{(a+2)^2+(0-9)^2}$

Taking square both sides and cancel square root

$a^2+4-4a+25=a^2+4+4a+81$

$-8a=81-25$

$a=-7$

The point on x-axis is (-7,0)

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