find the distance p{costheta, sintheta) q(sintheta,-costheta
Answers
Given: The points p (cos Ф, sin Ф) q ( sin Ф, -cos Ф )
To find: The distance between the two points?
Solution:
- Now we have given the points:
p (cos Ф, sin Ф) and q ( sin Ф, -cos Ф )
- We know the distance formula:
D = √(x2 - x1)² + (y2 - y1)²
- Putting the points , we get:
D = √(sin Ф - cos Ф)² + (-cos Ф - sin Ф)²
D = √(sin² Ф + cos² Ф - 2sin Ф cos Ф + cos² Ф + sin² Ф + 2cos Фsin Ф)
D = √1 + 1
D = √2
Answer:
So the distance is √2 units.
Answer:
Given: The points p (cos Ф, sin Ф) q ( sin Ф, -cos Ф )
To find: The distance between the two points?
Solution:
Now we have given the points:
p (cos Ф, sin Ф) and q ( sin Ф, -cos Ф )
We know the distance formula:
D = √(x2 - x1)² + (y2 - y1)²
Putting the points , we get:
D = √(sin Ф - cos Ф)² + (-cos Ф - sin Ф)²
D = √(sin² Ф + cos² Ф - 2sin Ф cos Ф + cos² Ф + sin² Ф + 2cos Фsin Ф)
D = √1 + 1
D = √2
Answer:
So the distance is √2 units.
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