Question

Find the distance the point (6,8)and the origin

Answer 1

Let A(6,8) be the given point and O(0,0) be the origin.

$= > \sqrt{(6 - 0)^2 + (8 - 0)^2}$

$= > \sqrt{6^2 + 8^2}$

$= > \sqrt{36 + 64}$

$= > \sqrt{100}$

= > 10 units

Hope this helps!

Answer 2

$\text {Your answer !!}$

$<b>$Points = ( 6, 8 )

Origins = ( 0, 0 )

$= > \sqrt{ {(8 - 0)}^{2} + {(6 - 0)}^{2} } \\ \\ = > \sqrt{ {(8)}^{2} + {(6)}^{2} } \\ \\ = > \sqrt{64 + 36} \\ \\ = > \sqrt{100} \\ \\ = > \sqrt{10 \times 10} \\ \\ = > 10$




Hence, 10 is your answer !!

$\text{Thanks !!}$